Why you cannot add decibels directly
A decibel value is a logarithm: it compares a sound with a reference on a log scale. Logarithms do not add like ordinary numbers, so two 85 dB machines are not 170 dB. What does add up is the sound energy (intensity) of independent sources. Convert each level to energy, add, then go back to decibels.
This holds for incoherent sources, such as different machines, voices or vehicles. Two loudspeakers playing the same signal in phase can add up to 6 dB, but that is a special case. For noise from separate sources, energy addition is the rule.
The decibel addition formula in Excel
Total dB = 10 × LOG10(10^(L1/10) + 10^(L2/10) + … + 10^(Ln/10))
- Convert each level in a helper column:
=10^(B2/10). The bench grinder at 91 dB has an energy of about 1.26 billion relative units. - Add the energies and convert back:
=10*LOG10(SUM(C2:C7))= 94.2 dB. - Without a helper column:
=10*LOG10(SUMPRODUCT(10^(B2:B7/10)))gives the same result in one cell.
The parentheses matter: 10^B2/10 raises 10 to the power 91 and then divides by 10.
Worked example: adding six machine noise levels
Six fictional workshop machines, each measured alone at the operator's position (yellow inputs). Column C converts each level into energy. Rows 9 to 13 add them correctly, show two wrong methods and switch off the grinder. Rows 15 to 17 check the rules of thumb, and rows 19 to 21 subtract background noise from a measurement.
| A | B | C | |
|---|---|---|---|
| 1 | Source | Level (dB) | Energy 10^(L/10) |
| 2 | Lathe | 84.0 | 251,188,643 |
| 3 | Air compressor | 82.0 | 158,489,319 |
| 4 | Bench grinder | 91.0 | 1,258,925,412 |
| 5 | Band saw | 88.0 | 630,957,344 |
| 6 | Extraction fan | 76.0 | 39,810,717 |
| 7 | Hydraulic press | 85.0 | 316,227,766 |
| 8 | |||
| 9 | Total of all six sources | 94.2 | |
| 10 | Wrong: plain sum of the dB values | 506.0 | |
| 11 | Wrong: average of the dB values | 84.3 | |
| 12 | Total without the bench grinder | 91.5 | |
| 13 | Drop when the grinder is switched off | 2.8 | |
| 14 | |||
| 15 | Two equal sources: 85 dB + 85 dB | 88.0 | |
| 16 | 10 dB apart: 85 dB + 75 dB | 85.4 | |
| 17 | Four equal sources of 80 dB: L + 10·log n | 86.0 | |
| 18 | |||
| 19 | Measured with the machine running | 87.0 | |
| 20 | Background, machine off | 82.0 | |
| 21 | Machine alone (background subtracted) | 85.3 | |
- C2
=10^(B2/10)Energy of one source - C9
=10*LOG10(SUM(C2:C7))Total level: energies added, then converted back - C12
=10*LOG10(SUM(C2:C7)-C4)Total without the bench grinder - C15
=10*LOG10(10^(85/10)+10^(85/10))Two equal sources: +3 dB - C17
=80+10*LOG10(4)n equal sources: L + 10·log10(n) - C21
=10*LOG10(10^(C19/10)-10^(C20/10))Background noise subtracted
Fictional levels. The formula assumes incoherent sources, which holds for different machines. Educational only: exposure limits vary, so check the noise rules that apply where you work.
Rules of thumb for adding two levels
The increase depends only on the difference between the two levels. Add this amount to the louder one:
- 0 dB apart: +3.0 dB (85 + 85 = 88.0)
- 1 dB apart: +2.5 dB
- 2 dB apart: +2.1 dB
- 3 dB apart: +1.8 dB
- 4 dB apart: +1.5 dB
- 6 dB apart: +1.0 dB
- 10 dB apart: +0.4 dB (85 + 75 = 85.4)
For n equal sources the total is L + 10 × log10(n): four machines of 80 dB give 86.0 dB, and doubling the number of equal sources always adds 3 dB.
Which source to fix first
Because the scale is logarithmic, the loudest source dominates. Remove the energy of the 91 dB grinder and recalculate: =10*LOG10(SUM(C2:C7)-C4) = 91.5 dB, a drop of 2.8 dB from one machine. Removing the 76 dB extraction fan instead changes the total by less than 0.1 dB. Noise control starts with the loudest machine, not with the most numerous ones.
Subtracting background noise
The same idea works backwards. Measure with the machine running, switch it off, measure the background, and subtract the energies: =10*LOG10(10^(C19/10)-10^(C20/10)). A reading of 87 dB with a background of 82 dB means the machine alone produces 85.3 dB.
When the two readings differ by less than about 3 dB the result is unreliable, so measure closer to the machine. When they differ by more than 10 dB, the background can be ignored.
dB(A) and noise exposure
Workplace noise is usually measured in A-weighted decibels, dB(A), which follow the sensitivity of the human ear. dB(A) values add with the same formula, as long as all of them are A-weighted and measured at the same position. Exposure over a shift is a time-weighted energy average of the same kind, and many occupational rules use 85 dB(A) over eight hours as an action or exposure level, with a 3 dB or 5 dB exchange rate depending on the rule. These limits are cited here in general terms, so check the rules that apply where you work. Safety teams often report noise exposure next to injury rates such as the TRIR.
Common mistakes
- Adding the dB values. 84 + 82 + 91 + 88 + 76 + 85 = 506 dB is meaningless. Add energies, then convert back: 94.2 dB.
- Averaging the dB values. The plain average is 84.3 dB. The energy average, the total minus 10 × log10(6), is 86.5 dB, because loud sources weigh more.
- Missing parentheses.
10^B2/10is not10^(B2/10). The first divides an enormous number by 10. - 20 instead of 10. 20 × log10 converts a pressure ratio into dB. For adding energies or intensities, the factor is 10.
- Mixing weightings or positions. dB(A) and dB(C), or levels measured at different distances, cannot be added as if they were the same thing.
- Subtracting a background that is too close. With less than about 3 dB between the total and the background, the machine level is too uncertain to report.
Frequently asked questions
How do you add two decibel levels?
Convert each level with 10^(L/10), add the two results and convert back with 10 × log10(sum). For 85 dB and 85 dB that gives 88.0 dB. For 85 dB and 75 dB it gives 85.4 dB.
Why is 85 dB + 85 dB only 88 dB?
Two equal sources double the sound energy, and doubling the energy adds 10 × log10(2) = 3.01 dB. The decibel scale is logarithmic, so levels never add arithmetically.
How do you subtract background noise in decibels?
Subtract the energies: L = 10 × log10(10^(Ltotal/10) − 10^(Lbackground/10)). With 87 dB total and 82 dB background, the source alone is 85.3 dB.
How much louder are two machines than one?
Two equal machines are 3 dB louder than one, four are 6 dB louder and ten are 10 dB louder. A 10 dB increase is perceived as roughly twice as loud.